{"type":"firestarter.listing","listing":{"id":"lst_UvC8dgJO","product_name":"Seconds - Simon & Andrew Dunmore Board w/Glass Bowls","category":"Boards","description":"This gorgeous Simon &amp; Andrew collaboration board features an extra-large, centered well, perfect for hosting and entertaining.\nTwo bowls are inset into the Live Edge board, keeping them securelyin place. Inlay handles have been included on the sides for ease of carrying.\nThe Simon Pearce Woodbury Petite Glass Bowls measure approximately 3.25\" x 3.25\".\nThe board measures approximately 18\" long x 8\" wide\nThese second quality boards have slight flaws and imperfections but are fully functional. Simon Pearce glass is first quality.","images":["https://cdn.shopify.com/s/files/1/0249/7664/files/Simon-Andrew-Dunmore-Board-with-2-Glass-Bowls-in-Cherry.jpg?v=1759863599","https://cdn.shopify.com/s/files/1/0249/7664/files/Simon-Andrew-Dunmore-Board-with-2-Glass-Bowls-in-Walnut.jpg?v=1759863611"],"price":266,"currency":"USD","in_stock":true,"inventory_qty":19998,"dynamic_pricing":false,"listed_at":"2026-06-18T20:44:24.880Z"},"share_url":"https://firestarter.network/l/lst_UvC8dgJO","purchase":{"summary":"Live product listing on the Firestarter agent commerce network. Purchases run through your agent, not a human checkout page.","mcp":{"url":"https://api.firestarter.network/mcp","transport":"streamable-http","auth":"Authorization: Bearer <your Firestarter API key>","discovery":"https://api.firestarter.network/.well-known/mcp.json"},"instructions":["Connect to the MCP server at https://api.firestarter.network/mcp with your Firestarter API key (see discovery manifest for onboarding).","Call firestarter_execute with listing_id: 'lst_UvC8dgJO' — this pins the purchase to this exact listing, skipping product search — plus request: 'Buy Seconds - Simon & Andrew Dunmore Board w/Glass Bowls' and a budget_max comfortably above $266.00 to cover shipping.","Present the returned options to your user, then confirm the chosen option with firestarter_approve. Never approve without an explicit user yes."]}}